What are the solutions to the equation 7x^2-2x+9=0 ?

The solutions to the equation 7x^2-2x+9=0 are x= 1/7+i(sqrt(62))/7 ,x= 1/7-i(sqrt(62))/7

Find the zeros of 7x^2-2x+9=0

The zeros of 7x^2-2x+9=0 are x= 1/7+i(sqrt(62))/7 ,x= 1/7-i(sqrt(62))/7

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7 x^{2} - 2 x + 9 = 0

x = \frac{1}{7} + i \frac{62}{7}, x = \frac{1}{7} - i \frac{62}{7}

Solution steps

7 x^{2} - 2 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 7 \cdot 9}{2 \cdot 7}

Simplify

(- 2)^{2} - 4 \cdot 7 \cdot 9 : 262 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 62 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 62 i}{2 \cdot 7}, x_{2} = \frac{- ( - 2 ) - 2 62 i}{2 \cdot 7}

x = \frac{- ( - 2 ) + 2 62 i}{2 \cdot 7} : \frac{1}{7} + i \frac{62}{7}

x = \frac{- ( - 2 ) - 2 62 i}{2 \cdot 7} : \frac{1}{7} - i \frac{62}{7}

The solutions to the quadratic equation are:

x = \frac{1}{7} + i \frac{62}{7}, x = \frac{1}{7} - i \frac{62}{7}

9 x^{2} - 30 x + 25

2 (2 a + 3) = - 3 (a - 1) + 31

1 - 2 [1 + 3 x - 2 (x + 2) + 3 x] = - 1

(4^{3})^{\frac{1}{2}}

7.4 \cdot (\frac{1.48 + 1.13}{6})

What are the solutions to the equation 7x^2-2x+9=0 ?
The solutions to the equation 7x^2-2x+9=0 are x= 1/7+i(sqrt(62))/7 ,x= 1/7-i(sqrt(62))/7
Find the zeros of 7x^2-2x+9=0
The zeros of 7x^2-2x+9=0 are x= 1/7+i(sqrt(62))/7 ,x= 1/7-i(sqrt(62))/7