What is the answer to (log_{10}(x^2))^2=1 ?

The answer to (log_{10}(x^2))^2=1 is x=sqrt(10),x=-sqrt(10),x= 1/(sqrt(10)),x=-1/(sqrt(10))

Solve for x: (log_{10}(x^2))^2=1

The solution is x=sqrt(10),x=-sqrt(10),x= 1/(sqrt(10)),x=-1/(sqrt(10))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(lo g_{10} (x^{2}))^{2} = 1

x = 10, x = - 10, x = \frac{1}{10}, x = - \frac{1}{10}

Decimal Notation

x = 3.16227 \dots, x = - 3.16227 \dots, x = 0.31622 \dots, x = - 0.31622 \dots

Solution steps

(lo g_{10} (x^{2}))^{2} = 1

Rewrite the equation with

lo g_{10} (x^{2}) = u

(u)^{2} = 1

Solve

u^{2} = 1 : u = 1, u = - 1

u = 1, u = - 1

Substitute back

u = lo g_{10} (x^{2}),

solve for

x

Solve

lo g_{10} (x^{2}) = 1 : x = 10, x = - 10

Solve

lo g_{10} (x^{2}) = - 1 : x = \frac{1}{10}, x = - \frac{1}{10}

x = 10, x = - 10, x = \frac{1}{10}, x = - \frac{1}{10}

Verify Solutions:

x = 10

True

, x = - 10

True

, x = \frac{1}{10}

True

, x = - \frac{1}{10}

True

The solutions are

x = 10, x = - 10, x = \frac{1}{10}, x = - \frac{1}{10}

ln (x + 2) = ln (12) - ln (x + 3)

lo g_{10} (C) = 10

lo g_{10} (x) = - lo g_{10} (ab)

lo g_{2} (\frac{x}{10000}) = 50

2 ln (2) + 2 ln (x) = 2 ln (2 x)

What is the answer to (log_{10}(x^2))^2=1 ?
The answer to (log_{10}(x^2))^2=1 is x=sqrt(10),x=-sqrt(10),x= 1/(sqrt(10)),x=-1/(sqrt(10))
Solve for x: (log_{10}(x^2))^2=1
The solution is x=sqrt(10),x=-sqrt(10),x= 1/(sqrt(10)),x=-1/(sqrt(10))