What is the answer to log_{5}(8y-6)+log_{5}(y-5)=4 ?

The answer to log_{5}(8y-6)+log_{5}(y-5)=4 is y=(23+sqrt(5289))/8

Solve for y: log_{5}(8y-6)+log_{5}(y-5)=4

The solution is y=(23+sqrt(5289))/8

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lo g_{5} (8 y - 6) + lo g_{5} (y - 5) = 4

y = \frac{23 + 5289}{8}

Decimal Notation

y = 11.96568 \dots

Solution steps

lo g_{5} (8 y - 6) + lo g_{5} (y - 5) = 4

Apply log rules

(8 y - 6) (y - 5) = 625

Solve

(8 y - 6) (y - 5) = 625 : y = \frac{23 + 5289}{8}, y = \frac{23 - 5289}{8}

y = \frac{23 + 5289}{8}, y = \frac{23 - 5289}{8}

Verify Solutions:

y = \frac{23 + 5289}{8}

True

, y = \frac{23 - 5289}{8}

False

The solution is

y = \frac{23 + 5289}{8}

2.1 = - lo g_{10} (h)

- 2 ln (a) = ln (9)

ln^{2} (x) = ln^{3} (x)

y, 3 ln (x + 4) = ln (y)

lo g_{y} (81) = - 4

What is the answer to log_{5}(8y-6)+log_{5}(y-5)=4 ?
The answer to log_{5}(8y-6)+log_{5}(y-5)=4 is y=(23+sqrt(5289))/8
Solve for y: log_{5}(8y-6)+log_{5}(y-5)=4
The solution is y=(23+sqrt(5289))/8