What is the answer to 3.81=-log_{10}(ka) ?

The answer to 3.81=-log_{10}(ka) is k= 1/(10^{3.81)a} {a 0}

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3.81=-log_{10}(ka)

3.81 = - lo g_{10} (ka)

k = \frac{1}{1 0 ^{3.81} a} {a < 0 or a > 0}

Solution steps

3.81 = - lo g_{10} (ka)

Move

lo g_{10} (ka)

to the left side

3.81 + lo g_{10} (ka) = 0

Move

3.81

to the right side

lo g_{10} (ka) = - 3.81

Apply log rules

ka = \frac{1}{1 0 ^{3.81}}

Solve

ka = \frac{1}{1 0 ^{3.81}} : k = \frac{1}{1 0 ^{3.81} a}

k = \frac{1}{1 0 ^{3.81} a}

Verify Solutions:

k = \frac{1}{1 0 ^{3.81} a} {a < 0 or a > 0}

The solution is

k = \frac{1}{1 0 ^{3.81} a} {a < 0 or a > 0}

lo g_{10} (x) = 2.644

lo g_{10} (y) (\frac{1}{256}) = - 4

lo g_{\frac{1}{2}} (3 x + 4) = - 2

ln (250 r) + ln (1) = 42 r

lo g_{12} (5 b - 8) = lo g_{12} (3 b)

What is the answer to 3.81=-log_{10}(ka) ?
The answer to 3.81=-log_{10}(ka) is k= 1/(10^{3.81)a} {a<0\lor a>0}