What is the answer to 1=-ln(1-x)-ln(x) ?

The answer to 1=-ln(1-x)-ln(x) is No Solution for x\in\mathbb{R}

Solve for x: 1=-ln(1-x)-ln(x)

The solution is No Solution for x\in\mathbb{R}

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1 = - ln (1 - x) - ln (x)

No Solution for x \in R

Solution steps

1 = - ln (1 - x) - ln (x)

Add

ln (1 - x)

to both sides

1 + ln (1 - x) = - ln (1 - x) - ln (x) + ln (1 - x)

Simplify

1 + ln (1 - x) = - ln (x)

Add

ln (x)

to both sides

1 + ln (1 - x) + ln (x) = - ln (x) + ln (x)

Simplify

1 + ln (1 - x) + ln (x) = 0

Apply log rules

(1 - x) x = \frac{1}{e}

Solve

(1 - x) x = \frac{1}{e} :

No Solution for

x \in R

No Solution for x \in R

2 lo g_{x} (9) = 3 lo g_{4} (16)

lo g_{2} (5 x + 4) = 5

lo g_{6} (x^{3}) - 2 lo g_{x} (6) = 1

lo g_{2} (5 x + 4) = 1

lo g_{5} (5 x) + lo g_{7} (7) = 9

What is the answer to 1=-ln(1-x)-ln(x) ?
The answer to 1=-ln(1-x)-ln(x) is No Solution for x\in\mathbb{R}
Solve for x: 1=-ln(1-x)-ln(x)
The solution is No Solution for x\in\mathbb{R}