What is the answer to log_{2}(2)=-log_{2}(x) ?

The answer to log_{2}(2)=-log_{2}(x) is x= 1/2

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log_{2}(2)=-log_{2}(x)

lo g_{2} (2) = - lo g_{2} (x)

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

lo g_{2} (2) = - lo g_{2} (x)

Move

lo g_{2} (x)

to the left side

lo g_{2} (2) + lo g_{2} (x) = 0

Move

lo g_{2} (2)

to the right side

lo g_{2} (x) = - lo g_{2} (2)

Apply log rules

x = \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

True

The solution is

x = \frac{1}{2}

ln (2 x - 1) = 1

ln (2 x - 1) = 5

lo g_{2} (n) = 1000

ln (t) = 10

10 lo g_{10} (x) = 108

What is the answer to log_{2}(2)=-log_{2}(x) ?
The answer to log_{2}(2)=-log_{2}(x) is x= 1/2
Solve for x: log_{2}(2)=-log_{2}(x)
The solution is x= 1/2