What is the answer to log_{10}(4-3x)=32 ?

The answer to log_{10}(4-3x)=32 is x=-(10^{32}-4)/3

Solve for x: log_{10}(4-3x)=32

The solution is x=-(10^{32}-4)/3

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lo g_{10} (4 - 3 x) = 32

x = - \frac{1 0 ^{32} - 4}{3}

Decimal Notation

x = - 3.33333 E 31

Solution steps

lo g_{10} (4 - 3 x) = 32

Apply log rules

4 - 3 x = 1 0^{32}

Solve

4 - 3 x = 1 0^{32} : x = - \frac{1 0 ^{32} - 4}{3}

x = - \frac{1 0 ^{32} - 4}{3}

ln (17 x + 8) = 1

lo g_{x} (2.1127) = 23.57

10 lo g_{10} (x) = 1.5

3 ln (x - 1) - 2 = 4

\frac{9}{8} lo g_{3} (x) = 3

What is the answer to log_{10}(4-3x)=32 ?
The answer to log_{10}(4-3x)=32 is x=-(10^{32}-4)/3
Solve for x: log_{10}(4-3x)=32
The solution is x=-(10^{32}-4)/3