What is the answer to log_{10}(x)=-log_{10}(a)b ?

The answer to log_{10}(x)=-log_{10}(a)b is x=a^{-b}

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log_{10}(x)=-log_{10}(a)b

lo g_{10} (x) = - lo g_{10} (a) b

x = a^{- b}

Solution steps

lo g_{10} (x) = - lo g_{10} (a) b

Apply log rules

x = a^{- b}

lo g_{8} (x) - 2 lo g_{x} (8) = 1

ln (2 v + 7) = ln (3 v)

3 lo g_{2} (x) = lo g_{2} (x^{3})

lo g_{4} (x) - lo g_{4} (x - 9) = 1

4 lo g_{3} (x) = lo g_{3} (x^{4})

What is the answer to log_{10}(x)=-log_{10}(a)b ?
The answer to log_{10}(x)=-log_{10}(a)b is x=a^{-b}