What is the answer to ln(x^2-2x)=1 ?

The answer to ln(x^2-2x)=1 is x=(2+sqrt(4+4e))/2 ,x=(2-sqrt(4+4e))/2

Solve for x: ln(x^2-2x)=1

The solution is x=(2+sqrt(4+4e))/2 ,x=(2-sqrt(4+4e))/2

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ln (x^{2} - 2 x) = 1

x = \frac{2 + 4 + 4 e}{2}, x = \frac{2 - 4 + 4 e}{2}

Decimal Notation

x = 2.92828 \dots, x = - 0.92828 \dots

Solution steps

ln (x^{2} - 2 x) = 1

Apply log rules

x^{2} - 2 x = e

Solve

x^{2} - 2 x = e : x = \frac{2 + 4 + 4 e}{2}, x = \frac{2 - 4 + 4 e}{2}

x = \frac{2 + 4 + 4 e}{2}, x = \frac{2 - 4 + 4 e}{2}

x, lo g_{10} (y) = ln (x)

lo g_{10} (n) = 6

lo g_{10} (n) = 1

0.05 = ln (1 + x)

ln (4 x - 8) = 2

What is the answer to ln(x^2-2x)=1 ?
The answer to ln(x^2-2x)=1 is x=(2+sqrt(4+4e))/2 ,x=(2-sqrt(4+4e))/2
Solve for x: ln(x^2-2x)=1
The solution is x=(2+sqrt(4+4e))/2 ,x=(2-sqrt(4+4e))/2