What is the answer to ln(3x+1)-2=10 ?

The answer to ln(3x+1)-2=10 is x=(e^{12}-1)/3

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ln(3x+1)-2=10

ln (3 x + 1) - 2 = 10

x = \frac{e ^{12} - 1}{3}

Decimal Notation

x = 54251.26380 \dots

Solution steps

ln (3 x + 1) - 2 = 10

Move

2

to the right side

ln (3 x + 1) = 12

Apply log rules

3 x + 1 = e^{12}

Solve

3 x + 1 = e^{12} : x = \frac{e ^{12} - 1}{3}

x = \frac{e ^{12} - 1}{3}

Verify Solutions:

x = \frac{e ^{12} - 1}{3}

True

The solution is

x = \frac{e ^{12} - 1}{3}

4 = 2 lo g_{2} (- x + 4) - 2

lo g_{x + 4} (2 x^{2} + 16) = 2

∣ lo g_{10} (x) ∣ = 0.2

lo g_{3} (x^{2}) - lo g_{3} (2 x) = 3

lo g_{9} (y) = 1

What is the answer to ln(3x+1)-2=10 ?
The answer to ln(3x+1)-2=10 is x=(e^{12}-1)/3
Solve for x: ln(3x+1)-2=10
The solution is x=(e^{12}-1)/3