What is the answer to 1.2=log_{10}(x+18) ?

The answer to 1.2=log_{10}(x+18) is x=10^{1.2}-18

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1.2=log_{10}(x+18)

1.2 = lo g_{10} (x + 18)

x = 1 0^{1.2} - 18

Decimal Notation

x = - 2.15106 \dots

Solution steps

1.2 = lo g_{10} (x + 18)

Apply log rules

1 0^{1.2} = x + 18

Solve

1 0^{1.2} = x + 18 : x = 1 0^{1.2} - 18

x = 1 0^{1.2} - 18

4 - ln_{7} (p) = 0

lo g_{9} (y) = 7

lo g_{10} (x^{2}) = 2 x - 1

2 lo g_{10} (x) - lo g_{10} (x) = 2

lo g_{10} (x) (100) = 2

What is the answer to 1.2=log_{10}(x+18) ?
The answer to 1.2=log_{10}(x+18) is x=10^{1.2}-18
Solve for x: 1.2=log_{10}(x+18)
The solution is x=10^{1.2}-18