What is the answer to ln(x^2-1)=ln(x+1) ?

The answer to ln(x^2-1)=ln(x+1) is x=2

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ln(x^2-1)=ln(x+1)

ln (x^{2} - 1) = ln (x + 1)

x = 2

Solution steps

ln (x^{2} - 1) = ln (x + 1)

Apply log rules

x^{2} - 1 = x + 1

Solve

x^{2} - 1 = x + 1 : x = 2, x = - 1

x = 2, x = - 1

Verify Solutions:

x = 2

True

, x = - 1

False

The solution is

x = 2

65 = 9 \cdot ln (x) + 44

2 lo g_{3} (x + 2) = lo g_{3} (3) + 1

ln (10 x + 6) = 5

lo g_{y} (2) = lo g_{4} (32)

ln^{2} (x) - ln (x) = 0

What is the answer to ln(x^2-1)=ln(x+1) ?
The answer to ln(x^2-1)=ln(x+1) is x=2
Solve for x: ln(x^2-1)=ln(x+1)
The solution is x=2