What is the answer to log_{2}(4x-3)=log_{2}(2x+1) ?

The answer to log_{2}(4x-3)=log_{2}(2x+1) is x=2

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log_{2}(4x-3)=log_{2}(2x+1)

lo g_{2} (4 x - 3) = lo g_{2} (2 x + 1)

x = 2

Solution steps

lo g_{2} (4 x - 3) = lo g_{2} (2 x + 1)

Apply log rules

4 x - 3 = 2 x + 1

Solve

4 x - 3 = 2 x + 1 : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

lo g_{4} (x + 1) = lo g_{4} (8)

- 2 x + 4 = ln (x)

lo g_{4} (x) = 7.5

x = \frac{1}{2} + 2 lo g_{4} (x)

ln (2) + ln (x + 1) = ln (5)

What is the answer to log_{2}(4x-3)=log_{2}(2x+1) ?
The answer to log_{2}(4x-3)=log_{2}(2x+1) is x=2
Solve for x: log_{2}(4x-3)=log_{2}(2x+1)
The solution is x=2