What is the answer to 2ln(t+2)=0 ?

The answer to 2ln(t+2)=0 is t=-1

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2ln(t+2)=0

2 ln (t + 2) = 0

t = - 1

Solution steps

2 ln (t + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

ln (t + 2) = 0

Solve

ln (t + 2) = 0 : t = - 1

Verify Solutions:

t = - 1

True

The solution is

t = - 1

lo g_{10} (a x) = 6

lo g_{9} (x - 2) = \frac{1}{2}

lo g_{2} (1 + x) = 10

- 20 = 20 lo g_{10} (\frac{v}{1})

8 lo g_{2} (x) = x