What is the answer to log_{5}(2x+1)+log_{5}(3)=2 ?

The answer to log_{5}(2x+1)+log_{5}(3)=2 is x= 11/3

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log_{5}(2x+1)+log_{5}(3)=2

lo g_{5} (2 x + 1) + lo g_{5} (3) = 2

x = \frac{11}{3}

Decimal Notation

x = 3.66666 \dots

Solution steps

lo g_{5} (2 x + 1) + lo g_{5} (3) = 2

Move

lo g_{5} (3)

to the right side

lo g_{5} (2 x + 1) = 2 - lo g_{5} (3)

Apply log rules

2 x + 1 = \frac{25}{3}

Solve

2 x + 1 = \frac{25}{3} : x = \frac{11}{3}

x = \frac{11}{3}

Verify Solutions:

x = \frac{11}{3}

True

The solution is

x = \frac{11}{3}

lo g_{7} (32) = 5 lo g_{7} (x)

ln (x) = 14.4247

lo g_{2} (x) - lo g_{2} (3 x) = 49

ln (x) = 8.495754696

ln (7 x) = ln (10)

What is the answer to log_{5}(2x+1)+log_{5}(3)=2 ?
The answer to log_{5}(2x+1)+log_{5}(3)=2 is x= 11/3
Solve for x: log_{5}(2x+1)+log_{5}(3)=2
The solution is x= 11/3