What are the solutions to the equation 2x^2+14=-7x ?

The solutions to the equation 2x^2+14=-7x are x=-7/4+i(3sqrt(7))/4 ,x=-7/4-i(3sqrt(7))/4

Find the zeros of 2x^2+14=-7x

The zeros of 2x^2+14=-7x are x=-7/4+i(3sqrt(7))/4 ,x=-7/4-i(3sqrt(7))/4

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2 x^{2} + 14 = - 7 x

x = - \frac{7}{4} + i \frac{3 7}{4}, x = - \frac{7}{4} - i \frac{3 7}{4}

Solution steps

2 x^{2} + 14 = - 7 x

Move

7 x

to the left side

2 x^{2} + 14 + 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + 7 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 \cdot 14}{2 \cdot 2}

Simplify

7^{2} - 4 \cdot 2 \cdot 14 : 37 i

x_{1, 2} = \frac{- 7 \pm 3 7 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 3 7 i}{2 \cdot 2}, x_{2} = \frac{- 7 - 3 7 i}{2 \cdot 2}

x = \frac{- 7 + 3 7 i}{2 \cdot 2} : - \frac{7}{4} + i \frac{3 7}{4}

x = \frac{- 7 - 3 7 i}{2 \cdot 2} : - \frac{7}{4} - i \frac{3 7}{4}

The solutions to the quadratic equation are:

x = - \frac{7}{4} + i \frac{3 7}{4}, x = - \frac{7}{4} - i \frac{3 7}{4}

\frac{- 54}{- 2}

x^{2} - 2 x - 15 > 2 x + 5

4 (1 - 6 n) + 6

49 x^{2} + 84 x y + 36 y^{2}

∣ 5 u + 10 ∣ > 15

What are the solutions to the equation 2x^2+14=-7x ?
The solutions to the equation 2x^2+14=-7x are x=-7/4+i(3sqrt(7))/4 ,x=-7/4-i(3sqrt(7))/4
Find the zeros of 2x^2+14=-7x
The zeros of 2x^2+14=-7x are x=-7/4+i(3sqrt(7))/4 ,x=-7/4-i(3sqrt(7))/4