What is the answer to log_{x}(81)=log_{2}(16) ?

The answer to log_{x}(81)=log_{2}(16) is x=3

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log_{x}(81)=log_{2}(16)

lo g_{x} (81) = lo g_{2} (16)

x = 3

Solution steps

lo g_{x} (81) = lo g_{2} (16)

Apply log rules

\frac{1}{lo g _{81} ( x )} = 4

Multiply both sides by

lo g_{81} (x)

\frac{1}{lo g _{81} ( x )} lo g_{81} (x) = 4 lo g_{81} (x)

Simplify

1 = 4 lo g_{81} (x)

Switch sides

4 lo g_{81} (x) = 1

Divide both sides by

4

lo g_{81} (x) = \frac{1}{4}

Apply log rules

x = 3

Verify Solutions:

x = 3

True

The solution is

x = 3

5.2 lo g_{4} (2 x) = 16

ln (e x - 10) = 2

lo g_{4} (4 x - 3) = 5

ln (5 - 2 x) = - 9

ln (5 - 2 x) = - 4

What is the answer to log_{x}(81)=log_{2}(16) ?
The answer to log_{x}(81)=log_{2}(16) is x=3
Solve for x: log_{x}(81)=log_{2}(16)
The solution is x=3