What is the answer to log_{10}(2x)+log_{10}(5)=1 ?

The answer to log_{10}(2x)+log_{10}(5)=1 is x=1

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log_{10}(2x)+log_{10}(5)=1

lo g_{10} (2 x) + lo g_{10} (5) = 1

x = 1

Solution steps

lo g_{10} (2 x) + lo g_{10} (5) = 1

Move

lo g_{10} (5)

to the right side

lo g_{10} (2 x) = 1 - lo g_{10} (5)

Apply log rules

2 x = 2

Solve

2 x = 2 : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

8.3 = - lo g_{10} (x)

2 lo g_{5} (x) = 1

x, y = ln (x - 6) + 4

lo g_{4} (x + 3) = 2 - lo g_{4} (x - 3)

2 ln (b) = ln (289)

What is the answer to log_{10}(2x)+log_{10}(5)=1 ?
The answer to log_{10}(2x)+log_{10}(5)=1 is x=1
Solve for x: log_{10}(2x)+log_{10}(5)=1
The solution is x=1