What is the answer to log_{16}(b)+log_{16}(b-15)=1 ?

The answer to log_{16}(b)+log_{16}(b-15)=1 is b=16

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log_{16}(b)+log_{16}(b-15)=1

lo g_{16} (b) + lo g_{16} (b - 15) = 1

b = 16

Solution steps

lo g_{16} (b) + lo g_{16} (b - 15) = 1

Apply log rules

b (b - 15) = 16

Solve

b (b - 15) = 16 : b = 16, b = - 1

b = 16, b = - 1

Verify Solutions:

b = 16

True

, b = - 1

False

The solution is

b = 16

t, x = ln (4 t)

lo g_{2} (5 - 3 x) = 3

lo g_{3} (9^{x} - 2) = x

lo g_{2} (5 - 3 x) = 1

2 \cdot lo g_{4} (3 x) = 3

What is the answer to log_{16}(b)+log_{16}(b-15)=1 ?
The answer to log_{16}(b)+log_{16}(b-15)=1 is b=16
Solve for b: log_{16}(b)+log_{16}(b-15)=1
The solution is b=16