What is the answer to 3log_{2}(2x+1)+2=3 ?

The answer to 3log_{2}(2x+1)+2=3 is x=(\sqrt[3]{2}-1)/2

Solve for x: 3log_{2}(2x+1)+2=3

The solution is x=(\sqrt[3]{2}-1)/2

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3 lo g_{2} (2 x + 1) + 2 = 3

Solution steps

3 lo g_{2} (2 x + 1) + 2 = 3

Move

2

to the right side

3 lo g_{2} (2 x + 1) = 1

Divide both sides by

3

lo g_{2} (2 x + 1) = \frac{1}{3}

Apply log rules

Solve

Verify Solutions:

True

The solution is

lo g_{10} (x) = \frac{19.55}{20}

3 = lo g_{2} (\frac{y}{3})

ln (2 x + 2) = ln (63)

x, lo g_{w} (x + 4) = t

6 ln (x) = 15.6

What is the answer to 3log_{2}(2x+1)+2=3 ?
The answer to 3log_{2}(2x+1)+2=3 is x=(\sqrt[3]{2}-1)/2
Solve for x: 3log_{2}(2x+1)+2=3
The solution is x=(\sqrt[3]{2}-1)/2