What is the answer to ln(x+4)+ln(x-4)=0 ?

The answer to ln(x+4)+ln(x-4)=0 is x=sqrt(17)

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ln(x+4)+ln(x-4)=0

ln (x + 4) + ln (x - 4) = 0

x = 17

Solution steps

ln (x + 4) + ln (x - 4) = 0

Apply log rules

(x + 4) (x - 4) = 1

Solve

(x + 4) (x - 4) = 1 : x = 17, x = - 17

x = 17, x = - 17

Verify Solutions:

x = 17

True

, x = - 17

False

The solution is

x = 17

2 \cdot lo g_{10} (x) = 12.2

lo g_{10} (x^{2} + 1) = 2

G (x) = lo g_{9} (x^{5})

5 + ln (x + 2) = 8

2 lo g_{3} (x + 5) - lo g_{3} (9) = 2

What is the answer to ln(x+4)+ln(x-4)=0 ?
The answer to ln(x+4)+ln(x-4)=0 is x=sqrt(17)
Solve for x: ln(x+4)+ln(x-4)=0
The solution is x=sqrt(17)