What is the answer to ln(2x+1)-ln(x-3)=2 ?

The answer to ln(2x+1)-ln(x-3)=2 is x=(3e^2+1)/(e^2-2)

Solve for x: ln(2x+1)-ln(x-3)=2

The solution is x=(3e^2+1)/(e^2-2)

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ln (2 x + 1) - ln (x - 3) = 2

x = \frac{3 e ^{2} + 1}{e ^{2} - 2}

Decimal Notation

x = 4.29892 \dots

Solution steps

ln (2 x + 1) - ln (x - 3) = 2

Add

ln (x - 3)

to both sides

ln (2 x + 1) - ln (x - 3) + ln (x - 3) = 2 + ln (x - 3)

Simplify

ln (2 x + 1) = 2 + ln (x - 3)

Apply log rules

2 x + 1 = e^{2} (x - 3)

Solve

2 x + 1 = e^{2} (x - 3) : x = \frac{3 e ^{2} + 1}{e ^{2} - 2}

x = \frac{3 e ^{2} + 1}{e ^{2} - 2}

Verify Solutions:

x = \frac{3 e ^{2} + 1}{e ^{2} - 2}

True

The solution is

x = \frac{3 e ^{2} + 1}{e ^{2} - 2}

1.034 = - 1.48 + 1.04 ln (x)

lo g_{4} (2 x - 12) = 3

m = lo g_{10} (\frac{s}{s})

lo g_{3} (2 x + 1) - lo g_{3} (x - 1) = 1

lo g_{10} (x) = - lo g_{10} (6)

What is the answer to ln(2x+1)-ln(x-3)=2 ?
The answer to ln(2x+1)-ln(x-3)=2 is x=(3e^2+1)/(e^2-2)
Solve for x: ln(2x+1)-ln(x-3)=2
The solution is x=(3e^2+1)/(e^2-2)