What is the answer to log_{4}(x^2-x+16)=2 ?

The answer to log_{4}(x^2-x+16)=2 is x=1,x=0

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log_{4}(x^2-x+16)=2

lo g_{4} (x^{2} - x + 16) = 2

x = 1, x = 0

Solution steps

lo g_{4} (x^{2} - x + 16) = 2

Apply log rules

x^{2} - x + 16 = 16

Solve

x^{2} - x + 16 = 16 : x = 1, x = 0

x = 1, x = 0

lo g_{10} (2 x) = 2 lo g_{10} (x)

lo g_{x} (3) = 5

2.77 - 1.61 + 0.5 ln (x) - ln (100) = 0

ln (3 x) = 6.4

- 2 = lo g_{x} (\frac{1}{25})

What is the answer to log_{4}(x^2-x+16)=2 ?
The answer to log_{4}(x^2-x+16)=2 is x=1,x=0
Solve for x: log_{4}(x^2-x+16)=2
The solution is x=1,x=0