What is the answer to solvefor x,y=ln(x^2) ?

The answer to solvefor x,y=ln(x^2) is x=sqrt(e^y),x=-sqrt(e^y)

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solvefor x,y=ln(x^2)

solve for

x, y = ln (x^{2})

x = e^{y}, x = - e^{y}

Solution steps

y = ln (x^{2})

Apply log rules

e^{y} = x^{2}

Solve

e^{y} = x^{2} : x = e^{y}, x = - e^{y}

x = e^{y}, x = - e^{y}

c = 2 (ln (x) + x)

y, ln (y) = - ln (x) + C

N, lo g_{10} (N) = 0.3 + 2 t

y, ln (c - 5 y) = 6 t

lo g_{5} (1 - x) = 4

What is the answer to solvefor x,y=ln(x^2) ?
The answer to solvefor x,y=ln(x^2) is x=sqrt(e^y),x=-sqrt(e^y)