What is the answer to ln(x^2)-7=0 ?

The answer to ln(x^2)-7=0 is x=e^3sqrt(e),x=-e^3sqrt(e)

Solve for x: ln(x^2)-7=0

The solution is x=e^3sqrt(e),x=-e^3sqrt(e)

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ln (x^{2}) - 7 = 0

x = e^{3} e, x = - e^{3} e

Decimal Notation

x = 33.11545 \dots, x = - 33.11545 \dots

Solution steps

ln (x^{2}) - 7 = 0

Move

7

to the right side

ln (x^{2}) = 7

Apply log rules

x^{2} = e^{7}

Solve

x^{2} = e^{7} : x = e^{3} e, x = - e^{3} e

x = e^{3} e, x = - e^{3} e

Verify Solutions:

x = e^{3} e

True

, x = - e^{3} e

True

The solutions are

x = e^{3} e, x = - e^{3} e

2 lo g_{10} (1 + x) = 2

0.2 = ln (x)

lo g_{6} (x + 1) = 2

2 ln (2) + ln (x) = ln (7 - 3 x)

16.9 = 10 lo g_{10} (x)

What is the answer to ln(x^2)-7=0 ?
The answer to ln(x^2)-7=0 is x=e^3sqrt(e),x=-e^3sqrt(e)
Solve for x: ln(x^2)-7=0
The solution is x=e^3sqrt(e),x=-e^3sqrt(e)