What are the solutions to the equation y^2-24y+144=-100 ?

The solutions to the equation y^2-24y+144=-100 are y=12+10i,y=12-10i

Find the zeros of y^2-24y+144=-100

The zeros of y^2-24y+144=-100 are y=12+10i,y=12-10i

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y^{2} - 24 y + 144 = - 100

y = 12 + 10 i, y = 12 - 10 i

Solution steps

y^{2} - 24 y + 144 = - 100

Move

100

to the left side

y^{2} - 24 y + 244 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 1 \cdot 244}{2 \cdot 1}

Simplify

(- 24)^{2} - 4 \cdot 1 \cdot 244 : 20 i

y_{1, 2} = \frac{- ( - 24 ) \pm 20 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 24 ) + 20 i}{2 \cdot 1}, y_{2} = \frac{- ( - 24 ) - 20 i}{2 \cdot 1}

y = \frac{- ( - 24 ) + 20 i}{2 \cdot 1} : 12 + 10 i

y = \frac{- ( - 24 ) - 20 i}{2 \cdot 1} : 12 - 10 i

The solutions to the quadratic equation are:

y = 12 + 10 i, y = 12 - 10 i

x^{\frac{2}{3}} x^{\frac{2}{3}}

1 - \frac{6 - 3 x}{3} = x

(14 x + 21 y) (6 ab - 3 a)

3 y^{2} - 12 y = 0

x^{2} \times x^{2}

What are the solutions to the equation y^2-24y+144=-100 ?
The solutions to the equation y^2-24y+144=-100 are y=12+10i,y=12-10i
Find the zeros of y^2-24y+144=-100
The zeros of y^2-24y+144=-100 are y=12+10i,y=12-10i