What is the answer to x+ln(x)=-4 ?

The answer to x+ln(x)=-4 is x=\W_{0}(1/(e^4))

Solve for x: x+ln(x)=-4

The solution is x=\W_{0}(1/(e^4))

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x + ln (x) = - 4

x = W_{0} (\frac{1}{e ^{4}})

Decimal Notation

x = 0.01798 \dots

Solution steps

x + ln (x) = - 4

Move

x

to the right side

ln (x) = - 4 - x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x)} = e^{- 4 - x}

Simplify

e^{l n (x)} : x

x = e^{- 4 - x}

Solve

x = e^{- 4 - x} : x = W_{0} (\frac{1}{e ^{4}})

x = W_{0} (\frac{1}{e ^{4}})

Verify Solutions:

x = W_{0} (\frac{1}{e ^{4}})

True

The solution is

x = W_{0} (\frac{1}{e ^{4}})

6 ln (x + 2) - 3 = 15

lo g_{5} (x + 3) = 3

lo g_{t} (25) = 2

lo g_{10} (u) = b

25 = 95 - 25 lo g_{2} (x)

What is the answer to x+ln(x)=-4 ?
The answer to x+ln(x)=-4 is x=\W_{0}(1/(e^4))
Solve for x: x+ln(x)=-4
The solution is x=\W_{0}(1/(e^4))