What is the answer to log_{3}(81)=4log_{3}(x+1) ?

The answer to log_{3}(81)=4log_{3}(x+1) is x=2

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log_{3}(81)=4log_{3}(x+1)

lo g_{3} (81) = 4 lo g_{3} (x + 1)

x = 2

Solution steps

lo g_{3} (81) = 4 lo g_{3} (x + 1)

Switch sides

4 lo g_{3} (x + 1) = lo g_{3} (81)

Divide both sides by

4

lo g_{3} (x + 1) = \frac{lo g _{3} ( 81 )}{4}

Apply log rules

x + 1 = 3

Solve

x + 1 = 3 : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

ln (1.8) - ln (x) = 0.2742

lo g_{10} (x - 1) = 3.4

3 lo g_{5} (25 x) = 12

lo g_{10} (x - 1) = 3, x

ln (x) - ln (x - 2000) = 1.4876

What is the answer to log_{3}(81)=4log_{3}(x+1) ?
The answer to log_{3}(81)=4log_{3}(x+1) is x=2
Solve for x: log_{3}(81)=4log_{3}(x+1)
The solution is x=2