What is the answer to x+1=4^{log_{2}(x-1)} ?

The answer to x+1=4^{log_{2}(x-1)} is x=3

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x+1=4^{log_{2}(x-1)}

x + 1 = 4^{l o g_{2} (x - 1)}

x = 3

Solution steps

x + 1 = 4^{l o g_{2} (x - 1)}

Apply log rules

x + 1 = (x - 1)^{2}

Solve

x + 1 = (x - 1)^{2} : x = 3, x = 0

x = 3, x = 0

Verify Solutions:

x = 3

True

, x = 0

False

The solution is

x = 3

ln (x) = a + b

10 = 8 + lo g_{10} (x)

lo g_{2} (x) - lo g_{4} (x^{2}) = 4

3 lo g_{9} (2) = lo g_{9} (x)

w, lo g_{co w} (m oo) = x

What is the answer to x+1=4^{log_{2}(x-1)} ?
The answer to x+1=4^{log_{2}(x-1)} is x=3
Solve for x: x+1=4^{log_{2}(x-1)}
The solution is x=3