What is the answer to solvefor x,z=ln(x^2y) ?

The answer to solvefor x,z=ln(x^2y) is x=sqrt((e^z)/y),x=-sqrt((e^z)/y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,z=ln(x^2y)

solve for

x, z = ln (x^{2} y)

x = \frac{e ^{z}}{y}, x = - \frac{e ^{z}}{y}

Solution steps

z = ln (x^{2} y)

Apply log rules

e^{z} = x^{2} y

Solve

e^{z} = x^{2} y : x = \frac{e ^{z}}{y}, x = - \frac{e ^{z}}{y}

x = \frac{e ^{z}}{y}, x = - \frac{e ^{z}}{y}

lo g_{2} ((4 x + 6)^{2}) = 4

0.324 - ln (\frac{T}{303.15}) = 0

lo g_{\frac{3}{5}} (x) = - 3

lo g_{10} (x + 1) + lo g_{10} (2 x) = 2

3 ln (p) + 7 ln (1 - p) = 0

What is the answer to solvefor x,z=ln(x^2y) ?
The answer to solvefor x,z=ln(x^2y) is x=sqrt((e^z)/y),x=-sqrt((e^z)/y)