What are the solutions to the equation 28x^2+16x+2=0 ?

The solutions to the equation 28x^2+16x+2=0 are x=(-4+sqrt(2))/(14),x=-(4+sqrt(2))/(14)

Find the zeros of 28x^2+16x+2=0

The zeros of 28x^2+16x+2=0 are x=(-4+sqrt(2))/(14),x=-(4+sqrt(2))/(14)

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28 x^{2} + 16 x + 2 = 0

x = \frac{- 4 + 2}{14}, x = - \frac{4 + 2}{14}

Solution steps

28 x^{2} + 16 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 28 \cdot 2}{2 \cdot 28}

1 6^{2} - 4 \cdot 28 \cdot 2 = 42

x_{1, 2} = \frac{- 16 \pm 4 2}{2 \cdot 28}

Separate the solutions

x_{1} = \frac{- 16 + 4 2}{2 \cdot 28}, x_{2} = \frac{- 16 - 4 2}{2 \cdot 28}

x = \frac{- 16 + 4 2}{2 \cdot 28} : \frac{- 4 + 2}{14}

x = \frac{- 16 - 4 2}{2 \cdot 28} : - \frac{4 + 2}{14}

The solutions to the quadratic equation are:

x = \frac{- 4 + 2}{14}, x = - \frac{4 + 2}{14}

r^{3} - 1

9 m^{2} - 49

b^{2} + 2 b - 24

(\frac{4 x ^{5}}{y ^{2} z})^{2}

3 x^{2} + 27 x + 54 = 0

What are the solutions to the equation 28x^2+16x+2=0 ?
The solutions to the equation 28x^2+16x+2=0 are x=(-4+sqrt(2))/(14),x=-(4+sqrt(2))/(14)
Find the zeros of 28x^2+16x+2=0
The zeros of 28x^2+16x+2=0 are x=(-4+sqrt(2))/(14),x=-(4+sqrt(2))/(14)