What is the answer to log_{b}(4)=3 ?

The answer to log_{b}(4)=3 is b=\sqrt[3]{4}

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log_{b}(4)=3

lo g_{b} (4) = 3

Solution steps

lo g_{b} (4) = 3

Apply log rules

\frac{1}{lo g _{4} ( b )} = 3

Multiply both sides by

lo g_{4} (b)

\frac{1}{lo g _{4} ( b )} lo g_{4} (b) = 3 lo g_{4} (b)

Simplify

1 = 3 lo g_{4} (b)

Switch sides

3 lo g_{4} (b) = 1

Divide both sides by

3

lo g_{4} (b) = \frac{1}{3}

Apply log rules

Verify Solutions:

True

The solution is

lo g_{2} (8 x + 3) = 5

lo g_{2} (5 x) - lo g_{2} (2) = 3

x, 4 ln (3 x) = 16

- 2 x + 5 \cdot ln (x + 1) - 2 = 0

x, 2 (lo g_{9} (30 x)) = 7

What is the answer to log_{b}(4)=3 ?
The answer to log_{b}(4)=3 is b=\sqrt[3]{4}
Solve for b: log_{b}(4)=3
The solution is b=\sqrt[3]{4}