What is the answer to 3log_{2}(x)+log_{2}(7)=4 ?

The answer to 3log_{2}(x)+log_{2}(7)=4 is x=2^{(4-log_{2}(7))/3}

Solve for x: 3log_{2}(x)+log_{2}(7)=4

The solution is x=2^{(4-log_{2}(7))/3}

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3 lo g_{2} (x) + lo g_{2} (7) = 4

x = 2^{\frac{4 - l o g _{2} ( 7 )}{3}}

Solution steps

3 lo g_{2} (x) + lo g_{2} (7) = 4

Move

lo g_{2} (7)

to the right side

3 lo g_{2} (x) = 4 - lo g_{2} (7)

Divide both sides by

3

lo g_{2} (x) = \frac{4 - lo g _{2} ( 7 )}{3}

Apply log rules

x = 2^{\frac{4 - l o g _{2} ( 7 )}{3}}

Verify Solutions:

x = 2^{\frac{4 - l o g _{2} ( 7 )}{3}}

True

The solution is

x = 2^{\frac{4 - l o g _{2} ( 7 )}{3}}

lo g_{n} (8) = 3

- 7.725 = lo g_{10} (x)

2 lo g_{3} (t) + lo g_{t} (9) = 5

ln (x) + ln^{2} (x) = 3

- 11 + \frac{12}{T} = - 4 ln (T)

What is the answer to 3log_{2}(x)+log_{2}(7)=4 ?
The answer to 3log_{2}(x)+log_{2}(7)=4 is x=2^{(4-log_{2}(7))/3}
Solve for x: 3log_{2}(x)+log_{2}(7)=4
The solution is x=2^{(4-log_{2}(7))/3}