What is the answer to 2=log_{10}(2^8 1/x) ?

The answer to 2=log_{10}(2^8 1/x) is x= 64/25

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2=log_{10}(2^8 1/x)

2 = lo g_{10} (2^{8} \frac{1}{x})

x = \frac{64}{25}

Solution steps

2 = lo g_{10} (2^{8} \cdot \frac{1}{x})

Apply log rules

100 = \frac{256}{x}

Solve

100 = \frac{256}{x} : x = \frac{64}{25}

x = \frac{64}{25}

6 (ln (2 x) + 1) = 0

lo g_{x} (8) = \frac{3}{2}

ln (x) = - a

3 lo g_{10} (2 y) = - 6

0 = ln (x) - \frac{1}{2} x + 1

What is the answer to 2=log_{10}(2^8 1/x) ?
The answer to 2=log_{10}(2^8 1/x) is x= 64/25
Solve for x: 2=log_{10}(2^8 1/x)
The solution is x= 64/25