What is the answer to ln(2x)-ln(x^2-3)=0 ?

The answer to ln(2x)-ln(x^2-3)=0 is x=3

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ln(2x)-ln(x^2-3)=0

ln (2 x) - ln (x^{2} - 3) = 0

x = 3

Solution steps

ln (2 x) - ln (x^{2} - 3) = 0

Add

ln (x^{2} - 3)

to both sides

ln (2 x) - ln (x^{2} - 3) + ln (x^{2} - 3) = 0 + ln (x^{2} - 3)

Simplify

ln (2 x) = ln (x^{2} - 3)

Apply log rules

2 x = x^{2} - 3

Solve

2 x = x^{2} - 3 : x = 3, x = - 1

x = 3, x = - 1

Verify Solutions:

x = 3

True

, x = - 1

False

The solution is

x = 3

lo g_{10} (x^{3} + 200) = 2

x, ln (x) = - (3 y + ln (y))

lo g_{10} (x) + lo g_{10} (x + 4) = 1

ln (x) = 6 + 2 ln (2)

lo g_{4} (5 x + 2) = 5 x

What is the answer to ln(2x)-ln(x^2-3)=0 ?
The answer to ln(2x)-ln(x^2-3)=0 is x=3
Solve for x: ln(2x)-ln(x^2-3)=0
The solution is x=3