What is the answer to log_{10}(x+2)=2.19 ?

The answer to log_{10}(x+2)=2.19 is x=10^{2.19}-2

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log_{10}(x+2)=2.19

lo g_{10} (x + 2) = 2.19

x = 1 0^{2.19} - 2

Solution steps

lo g_{10} (x + 2) = 2.19

Apply log rules

x + 2 = 1 0^{2.19}

Solve

x + 2 = 1 0^{2.19} : x = 1 0^{2.19} - 2

x = 1 0^{2.19} - 2

ln (4 x + 5) = 10

60 = 9.95593 ln (x) + 68.691

a = lo g_{10} (x - 4)

ln (x) = 30

ln (x - 6) + ln (x + 3) = ln (x - 22)

What is the answer to log_{10}(x+2)=2.19 ?
The answer to log_{10}(x+2)=2.19 is x=10^{2.19}-2
Solve for x: log_{10}(x+2)=2.19
The solution is x=10^{2.19}-2