What is the answer to log_{x}(2+2)=3 ?

The answer to log_{x}(2+2)=3 is x=e^{(2ln(2))/3}

Solve for x: log_{x}(2+2)=3

The solution is x=e^{(2ln(2))/3}

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lo g_{x} (2 + 2) = 3

x = e^{\frac{2 l n ( 2 )}{3}}

Decimal Notation

x = 1.58740 \dots

Solution steps

lo g_{x} (2 + 2) = 3

Apply log rules

\frac{ln ( 2 + 2 )}{ln ( x )} = 3

Multiply both sides by

ln (x)

\frac{ln ( 2 + 2 )}{ln ( x )} ln (x) = 3 ln (x)

Apply log rules

x = e^{\frac{2 l n ( 2 )}{3}}

Verify Solutions:

x = e^{\frac{2 l n ( 2 )}{3}}

True

The solution is

x = e^{\frac{2 l n ( 2 )}{3}}

- 3 - ln (- 3 + x) = 0

a^{5} = lo g_{5} (x^{5})

lo g_{X} (16) = - 1

ln (5 x - 4) = ln (8) - ln (x - 2)

lo g_{10} (x) = \frac{- 1}{n}

What is the answer to log_{x}(2+2)=3 ?
The answer to log_{x}(2+2)=3 is x=e^{(2ln(2))/3}
Solve for x: log_{x}(2+2)=3
The solution is x=e^{(2ln(2))/3}