What is the answer to log_{2}(x+5)=-log_{2}(x+3)+3 ?

The answer to log_{2}(x+5)=-log_{2}(x+3)+3 is x=-1

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log_{2}(x+5)=-log_{2}(x+3)+3

lo g_{2} (x + 5) = - lo g_{2} (x + 3) + 3

x = - 1

Solution steps

lo g_{2} (x + 5) = - lo g_{2} (x + 3) + 3

Add

lo g_{2} (x + 3)

to both sides

lo g_{2} (x + 5) + lo g_{2} (x + 3) = - lo g_{2} (x + 3) + 3 + lo g_{2} (x + 3)

Simplify

lo g_{2} (x + 5) + lo g_{2} (x + 3) = 3

Apply log rules

(x + 5) (x + 3) = 8

Solve

(x + 5) (x + 3) = 8 : x = - 1, x = - 7

x = - 1, x = - 7

Verify Solutions:

x = - 1

True

, x = - 7

False

The solution is

x = - 1

- 0.04 = lo g_{10} (x)

lo g_{3} (x) - 2 lo g_{10} (x) (3) = 1

lo g_{10} (x) = 22.2

29728 = - 1.987 (298) ln (x)

4 + ln (x + 1) = 6

What is the answer to log_{2}(x+5)=-log_{2}(x+3)+3 ?
The answer to log_{2}(x+5)=-log_{2}(x+3)+3 is x=-1
Solve for x: log_{2}(x+5)=-log_{2}(x+3)+3
The solution is x=-1