What is the answer to log_{2}(x+2)+log_{2}(x-4)=4 ?

The answer to log_{2}(x+2)+log_{2}(x-4)=4 is x=6

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log_{2}(x+2)+log_{2}(x-4)=4

lo g_{2} (x + 2) + lo g_{2} (x - 4) = 4

x = 6

Solution steps

lo g_{2} (x + 2) + lo g_{2} (x - 4) = 4

Apply log rules

(x + 2) (x - 4) = 16

Solve

(x + 2) (x - 4) = 16 : x = 6, x = - 4

x = 6, x = - 4

Verify Solutions:

x = 6

True

, x = - 4

False

The solution is

x = 6

lo g_{2} (x + 2) + lo g_{2} (x - 4) = 2

lo g_{2} (x + 2) + lo g_{2} (x - 4) = 3

lo g_{4} (x^{3} + 37) = 3

ln (x) = 12.39

lo g_{16} (x) = (lo g_{4} (x))

What is the answer to log_{2}(x+2)+log_{2}(x-4)=4 ?
The answer to log_{2}(x+2)+log_{2}(x-4)=4 is x=6
Solve for x: log_{2}(x+2)+log_{2}(x-4)=4
The solution is x=6