What is the answer to -6=-sqrt(ln((0)^2+c_{1))} ?

The answer to -6=-sqrt(ln((0)^2+c_{1))} is c_{1}=e^{36}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-6=-sqrt(ln((0)^2+c_{1))}

- 6 = - ln ((0)^{2} + c_{1})

c_{1} = e^{36}

Decimal Notation

c_{1} = 4.31123 E 15

Solution steps

- 6 = - ln ((0)^{2} + c_{1})

Rewrite the equation with

ln (0^{2} + c_{1}) = u

- 6 = - u

Solve

- 6 = - u : u = 36

u = 36

Substitute back

u = ln (0^{2} + c_{1}),

solve for

c_{1}

Solve

ln (0^{2} + c_{1}) = 36 : c_{1} = e^{36}

c_{1} = e^{36}

Verify Solutions:

c_{1} = e^{36}

True

The solution is

c_{1} = e^{36}

lo g_{3 x + 2} (8) = lo g_{5} (2)

lo g_{b} (3) = 10

lo g_{2} (x - 1) + lo g_{2} (2 x - 1) = 0

7.3 = lo g_{10} (x)

lo g_{6} (8 - 3 x) = 1

What is the answer to -6=-sqrt(ln((0)^2+c_{1))} ?
The answer to -6=-sqrt(ln((0)^2+c_{1))} is c_{1}=e^{36}