What is the answer to log_{10}(log_{10}(a))=-0.2 ?

The answer to log_{10}(log_{10}(a))=-0.2 is a=10^{1/(10^{0.2)}}

Solve for a: log_{10}(log_{10}(a))=-0.2

The solution is a=10^{1/(10^{0.2)}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{10} (lo g_{10} (a)) = - 0.2

a = 1 0^{\frac{1}{1 0 ^{0.2}}}

Solution steps

lo g_{10} (lo g_{10} (a)) = - 0.2

Apply log rules

a = 1 0^{\frac{1}{1 0 ^{0.2}}}

Verify Solutions:

a = 1 0^{\frac{1}{1 0 ^{0.2}}}

True

The solution is

a = 1 0^{\frac{1}{1 0 ^{0.2}}}

1 = lo g_{3} (x)

lo g_{3} (x) - lo g_{3} (9) = 10

lo g_{10} (6 w) = - 2

- 15.2 = - 20 lo g_{10} (x)

lo g_{10} (x) (6 x + 16) = 2

What is the answer to log_{10}(log_{10}(a))=-0.2 ?
The answer to log_{10}(log_{10}(a))=-0.2 is a=10^{1/(10^{0.2)}}
Solve for a: log_{10}(log_{10}(a))=-0.2
The solution is a=10^{1/(10^{0.2)}}