What is the answer to ln(x)+x=0.01 ?

The answer to ln(x)+x=0.01 is x=\W_{0}(e^{0.01})

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ln(x)+x=0.01

ln (x) + x = 0.01

x = W_{0} (e^{0.01})

Solution steps

ln (x) + x = 0.01

Move

x

to the right side

ln (x) = 0.01 - x

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{l n (x)} = e^{0.01 - x}

Simplify

e^{l n (x)} : x

x = e^{0.01 - x}

Solve

x = e^{0.01 - x} : x = W_{0} (e^{0.01})

x = W_{0} (e^{0.01})

Verify Solutions:

x = W_{0} (e^{0.01})

True

The solution is

x = W_{0} (e^{0.01})

ln (3 x) = 1.3

x, ln (x) = e^{y}

x, lo g_{10} (16 x) = 0.5

- 5 lo g_{8} (3 m) = 5

x e^{a} = e^{a l n (x)}

What is the answer to ln(x)+x=0.01 ?
The answer to ln(x)+x=0.01 is x=\W_{0}(e^{0.01})
Solve for x: ln(x)+x=0.01
The solution is x=\W_{0}(e^{0.01})