What is the answer to -2=ln|x| ?

The answer to -2=ln|x| is x=-1/(e^2),x= 1/(e^2)

Solve for x: -2=ln|x|

The solution is x=-1/(e^2),x= 1/(e^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 2 = ln ∣ x ∣

x = - \frac{1}{e ^{2}}, x = \frac{1}{e ^{2}}

Solution steps

- 2 = ln ∣ x ∣

Apply log rules

\frac{1}{e ^{2}} = ∣ x ∣

Solve

\frac{1}{e ^{2}} = ∣ x ∣ : x = - \frac{1}{e ^{2}} or x = \frac{1}{e ^{2}}

x = - \frac{1}{e ^{2}}, x = \frac{1}{e ^{2}}

ln (x + 8) + ln (10) = 3

x, f x = ln (14 x)

25 - ln (3 - x) = 0

lo g_{\frac{2}{5}} (x) = 2

0.22 = ln (x)

What is the answer to -2=ln|x| ?
The answer to -2=ln|x| is x=-1/(e^2),x= 1/(e^2)
Solve for x: -2=ln|x|
The solution is x=-1/(e^2),x= 1/(e^2)