What are the solutions to the equation r^2-r-2=0 ?

The solutions to the equation r^2-r-2=0 are r=2,r=-1

Find the zeros of r^2-r-2=0

The zeros of r^2-r-2=0 are r=2,r=-1

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r^{2} - r - 2 = 0

r = 2, r = - 1

Solution steps

r^{2} - r - 2 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 2) = 3

r_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 1}, r_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 1}

r = \frac{- ( - 1 ) + 3}{2 \cdot 1} : 2

r = \frac{- ( - 1 ) - 3}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

r = 2, r = - 1

45 c^{6} + 54 c^{8}

\frac{5}{6} \cdot \frac{2}{5}

(\frac{19}{2})^{2}

1 - x^{6}

x^{2 + 2 x + 4}

What are the solutions to the equation r^2-r-2=0 ?
The solutions to the equation r^2-r-2=0 are r=2,r=-1
Find the zeros of r^2-r-2=0
The zeros of r^2-r-2=0 are r=2,r=-1