What is the answer to 45=20+47log_{10}(x+2) ?

The answer to 45=20+47log_{10}(x+2) is x=10^{25/47}-2

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45=20+47log_{10}(x+2)

45 = 20 + 47 lo g_{10} (x + 2)

x = 1 0^{\frac{25}{47}} - 2

Solution steps

45 = 20 + 47 lo g_{10} (x + 2)

Switch sides

20 + 47 lo g_{10} (x + 2) = 45

Move

20

to the right side

47 lo g_{10} (x + 2) = 25

Divide both sides by

47

lo g_{10} (x + 2) = \frac{25}{47}

Apply log rules

x + 2 = 1 0^{\frac{25}{47}}

Solve

x + 2 = 1 0^{\frac{25}{47}} : x = 1 0^{\frac{25}{47}} - 2

x = 1 0^{\frac{25}{47}} - 2

Verify Solutions:

x = 1 0^{\frac{25}{47}} - 2

True

The solution is

x = 1 0^{\frac{25}{47}} - 2

- lo g_{10} (x) = 3.5

ln (\frac{x}{0.0315}) = 229

(ln (x^{3}))^{2} = e

lo g_{6} (16) = 4 lo g_{6} (x)

lo g_{16} (r) = \frac{1}{4}

What is the answer to 45=20+47log_{10}(x+2) ?
The answer to 45=20+47log_{10}(x+2) is x=10^{25/47}-2
Solve for x: 45=20+47log_{10}(x+2)
The solution is x=10^{25/47}-2