What is the answer to ln(x-1)+ln(x-2)=ln(7) ?

The answer to ln(x-1)+ln(x-2)=ln(7) is x=(3+sqrt(29))/2

Solve for x: ln(x-1)+ln(x-2)=ln(7)

The solution is x=(3+sqrt(29))/2

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ln (x - 1) + ln (x - 2) = ln (7)

x = \frac{3 + 29}{2}

Decimal Notation

x = 4.19258 \dots

Solution steps

ln (x - 1) + ln (x - 2) = ln (7)

Apply log rules

(x - 1) (x - 2) = 7

Solve

(x - 1) (x - 2) = 7 : x = \frac{3 + 29}{2}, x = \frac{3 - 29}{2}

x = \frac{3 + 29}{2}, x = \frac{3 - 29}{2}

Verify Solutions:

x = \frac{3 + 29}{2}

True

, x = \frac{3 - 29}{2}

False

The solution is

x = \frac{3 + 29}{2}

1.3648 = 0.6446 ln (x) - 0.5557

3 ln (x) - 2 = 0

c + 5 ln (- 1 + c) = 3.46

lo g_{8} (x + 4) = lo g_{8} (6)

- 1 + 2 ln (x) = - 2.3863

What is the answer to ln(x-1)+ln(x-2)=ln(7) ?
The answer to ln(x-1)+ln(x-2)=ln(7) is x=(3+sqrt(29))/2
Solve for x: ln(x-1)+ln(x-2)=ln(7)
The solution is x=(3+sqrt(29))/2