What is the answer to log_{10}(m)=-1+log_{10}(m+3) ?

The answer to log_{10}(m)=-1+log_{10}(m+3) is m= 1/3

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log_{10}(m)=-1+log_{10}(m+3)

lo g_{10} (m) = - 1 + lo g_{10} (m + 3)

m = \frac{1}{3}

Solution steps

lo g_{10} (m) = - 1 + lo g_{10} (m + 3)

Apply log rules

m \cdot 10 = m + 3

Solve

m \cdot 10 = m + 3 : m = \frac{1}{3}

m = \frac{1}{3}

Verify Solutions:

m = \frac{1}{3}

True

The solution is

m = \frac{1}{3}

lo g_{2} (4 x + 5) - lo g_{2} (4 - x) = 3

ln (x) = ln^{2} (x)

lo g_{6} (5 x) = 3

lo g_{10} (x) + lo g_{10} (x + 90) = 3

t, ln (2 t + 3) = 4

What is the answer to log_{10}(m)=-1+log_{10}(m+3) ?
The answer to log_{10}(m)=-1+log_{10}(m+3) is m= 1/3
Solve for m: log_{10}(m)=-1+log_{10}(m+3)
The solution is m= 1/3