What is the answer to log_{4}(x-5)+log_{4}(x+3)=1 ?

The answer to log_{4}(x-5)+log_{4}(x+3)=1 is x=1+2sqrt(5)

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log_{4}(x-5)+log_{4}(x+3)=1

lo g_{4} (x - 5) + lo g_{4} (x + 3) = 1

x = 1 + 25

Decimal Notation

x = 5.47213 \dots

Solution steps

lo g_{4} (x - 5) + lo g_{4} (x + 3) = 1

Apply log rules

(x - 5) (x + 3) = 4

Solve

(x - 5) (x + 3) = 4 : x = 1 + 25, x = 1 - 25

x = 1 + 25, x = 1 - 25

Verify Solutions:

x = 1 + 25

True

, x = 1 - 25

False

The solution is

x = 1 + 25

lo g_{10} (200) = 4 - 3 lo g_{10} (x)

lo g_{7} (w) - lo g_{7} (13) = 1

10 - 2 lo g_{10} (x - 3) = 8

lo g_{x} (2) = - 3

lo g_{a} (36) = 2

What is the answer to log_{4}(x-5)+log_{4}(x+3)=1 ?
The answer to log_{4}(x-5)+log_{4}(x+3)=1 is x=1+2sqrt(5)
Solve for x: log_{4}(x-5)+log_{4}(x+3)=1
The solution is x=1+2sqrt(5)