What are the solutions to the equation a^2+20a=44 ?

The solutions to the equation a^2+20a=44 are a=2,a=-22

Find the zeros of a^2+20a=44

The zeros of a^2+20a=44 are a=2,a=-22

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a^{2} + 20 a = 44

a = 2, a = - 22

Solution steps

a^{2} + 20 a = 44

Move

44

to the left side

a^{2} + 20 a - 44 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot ( - 44 )}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot (- 44) = 24

a_{1, 2} = \frac{- 20 \pm 24}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 20 + 24}{2 \cdot 1}, a_{2} = \frac{- 20 - 24}{2 \cdot 1}

a = \frac{- 20 + 24}{2 \cdot 1} : 2

a = \frac{- 20 - 24}{2 \cdot 1} : - 22

The solutions to the quadratic equation are:

a = 2, a = - 22

(5 - 2)^{2}

(3 + 5) (1 + 5)

- 8 \leq 3 x + 1 \leq - 2

- 54 + 250 a^{3}

4 x^{2} + 16 x + 15

What are the solutions to the equation a^2+20a=44 ?
The solutions to the equation a^2+20a=44 are a=2,a=-22
Find the zeros of a^2+20a=44
The zeros of a^2+20a=44 are a=2,a=-22