What is the answer to log_{3}(x+7)+log_{3}(x+1)=2 ?

The answer to log_{3}(x+7)+log_{3}(x+1)=2 is x=-4+3sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{3}(x+7)+log_{3}(x+1)=2

lo g_{3} (x + 7) + lo g_{3} (x + 1) = 2

x = - 4 + 32

Solution steps

lo g_{3} (x + 7) + lo g_{3} (x + 1) = 2

Apply log rules

(x + 7) (x + 1) = 9

Solve

(x + 7) (x + 1) = 9 : x = - 4 + 32, x = - 4 - 32

x = - 4 + 32, x = - 4 - 32

Verify Solutions:

x = - 4 + 32

True

, x = - 4 - 32

False

The solution is

x = - 4 + 32

ln^{2} (x - 1) - 2 ln (x - 1) = 0

lo g_{10} (a) = 11.3

x, - 1 = ln (x - y)

lo g_{x - 1} (x + 2) = - 1

104 = 20 lo g_{10} (x)

What is the answer to log_{3}(x+7)+log_{3}(x+1)=2 ?
The answer to log_{3}(x+7)+log_{3}(x+1)=2 is x=-4+3sqrt(2)
Solve for x: log_{3}(x+7)+log_{3}(x+1)=2
The solution is x=-4+3sqrt(2)